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On the basic of thermochemical equations (I),(II)and (III), Find out which of the algebraic relationships given in options (a)to (d) is correct ? (I)C("graphite")+O(2)(g)to CO(2)(g), Delta(r)H=XKJmol^(-1) (II)C("graphite")+(1)/(2)O(2)(g)toCO(g), Delta ...
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Consider the reaction given below. On the basis of these reactions find out which of the algebraic relations given in options (A) to (D) is correct?(i) C(g) + 4H(g)→ CH4(g); ΔrH =
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Three thermochemical equations are given below
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SOLVED: Given the thermochemical equations Xz + 3Y2 L+ 2XY3 AH[ = -320 kJ X, + 222 2XZz AHz = -0 kJ 2Yz +Z2 > 2YzZ AH; = #230 kJ Calculate the change in enthalpy for the reaction: 4XY; + 722 57 6YzZ + 4XZz
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Given that:(i) C (graphite) + O2(g)→ CO2(g) ; Δ rH^o = x kJ mol^-1 .(ii) C (graphite) + 12O2(g)→ CO(g) ; Δ rH^o = y kJ mol^-1 (iii) CO(g) + 12O2(g)→ CO2(g) ;
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SOLVED: Thermochemical Equations Calculate for the enthalpy changes and write the final thermochemical equations The complete combustion of acetic acid, HCzH3Oz(l) , to form water, HzO(l) , and COz(g) , at constant
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SOLVED:Write thermochemical equations for the formation of one mole of the following compounds from the elements in their native states at 25^∘ C and 1 atm . (a) solid potassium chlorate (b)
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Consider the reaction given below. On the basis of these reactions find out which of the algebraic relations given in options (A) to (D) is correct?(i) C(g) + 4H(g)→ CH4(g); ΔrH =
Given C(("graphite"))+O(2)(g)toCO(2)(g), Delta(r)H^(0)=-393.5kJ" "mol^(-1) H(2)(g)=+(1)/(2)O(2)(g)toH(2)O(1), Delta(r)H^(0)=-285.8" kJ "mol^(-1) CO(2)(g)+2H(2)O(1)toCH(4)(g)+2O(2)(g), Delta(r)H^(0)=+890.3kJ" "mol^(-1) Based on the above thermochemical ...
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SOLVED:Write thermochemical equations for the decomposition of one mole of the following compounds into the elements in their stable states at 25^∘ C and 1 atm. (a) ethyl alcohol, C2 H5 OH(l) (
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Given the thermochemical equation. C2 H2+ 5/2O2 (g) rarr 2CO2 (g) + H2O(I) DeltarH^@=-1300 kJ Write thermochemical equations when (i) Coefficients of substances are multiplied by 2 (ii) Equation is reversed.
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